7. In AP, an = 3 + 4n then sum of first two terms of AP
is
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3+4n
Putting value of n as 1
3+4×1=7
Now putting value of n as 2
3+4×2=11
So,ap=7,11,15,19.......
Sn=n/2{2a +n-1+×d}
S15=15/2{14 +14×4}
S15=15/2×70
S15=15×35
S15=525
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