Question

7. In figure, CD is a diameter
of the circle which meets
the chord AB in E, such that
AE = BE=4 cm. If CE =3 cm,
find the radius of the circle.​

Answer 1

Answer:

12CM

Step-by-step explanation:

Answer 2

Answer:

Given that : - CD is diameter which meets chord AB in E . AE = BE = 4 cm , CE = 3 cm.

To find : - Radius of the circle.

Let the radius be R.

Mark a point O a the mid point of the circle and join OB. OB = OC = R .

So , OE = ( R - 3).

Then, by Pythagoras theorem,

(R - 3)² + (4)² = (R)²

=> R² - 6R + 9 + 16 = R²

=> R² - R² - 6R = - 25

=> 6R = 25

=> R = 25/6

=> R = 4.16 cm

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