Math, asked by nutanm1983, 4 months ago

7. In the figure, PQ = 7.5cm, QR = 12cm, PR = 10cm. Which of the following
statements is true? *
P
7.5cm
10cm
Q
12cm
R
O PQR > PRQ > ZRQP
N
OPRQ > PQR > ZQPR
O ZQPR > ZPRQ > PQR
O ZOPR > ZPQR > ZPRQ​

Answers

Answered by Anonymous
12

Answer:

In the figure, PQ = 7.5cm, QR = 12cm, PR = 10cm. Which of the following

statements is true? *

P

7.5cm

10cm

Q

12cm

R

O PQR > PRQ > ZRQP

N

OPRQ > PQR > ZQPR

O ZQPR > ZPRQ > PQR

Step-by-step explanation:

In the figure, PQ = 7.5cm, QR = 12cm, PR = 10cm. Which of the following

statements is true? *

P

7.5cm In the figure, PQ = 7.5cm, QR = 12cm, PR = 10cm. Which of the following

statements is true? *

P

7.5cm

10cm

Q

12cm

R

O PQR > PRQ > ZRQP

N

OPRQ > PQR > ZQPR

O ZQPR > ZPRQ > PQR

10cm

Q

12cm

R

O PQR > PRQ > ZRQP

N

OPRQ > PQR > ZQPR

O ZQPR > ZPRQ > PQR

Answered by RvChaudharY50
1

Given :- In ∆PQR we have, PQ = 7.5cm, QR = 12cm, PR = 10cm.

To Find :- Which of the following statements is true :-

A) ∠PQR > ∠PRQ > ∠RQP

B) ∠PRQ > ∠PQR > ∠QPR

C) ∠QPR > ∠PRQ > ∠PQR

D) ∠QPR > ∠PQR > ∠PRQ

Concept used :- In a triangle :-

  • The angle opposite to the greater side is the greatest in measure .

Solution :-

given that, In ∆PQR,

→ PQ = 7.5 cm

→ PR = 10 cm

→ QR = 12 cm

So,

→ 12 cm > 10 cm > 7.5 cm

or,

→ QR > PR > PQ -------- Equation (1)

now,

→ Angle opposite to side QR = ∠QPR

→ Angle opposite to side PR = ∠PQR

→ Angle opposite to side PQ = ∠PRQ

since from equation (1) we have,

→ QR > PR > PQ

therefore, from above told concept ,

∠QPR > ∠PQR > ∠PRQ (Ans.)

Hence, Statement (D) is true for given ∆PQR .

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