7. In the given figure, AOB is a straight line and the ray OC stands on it. If Angle - AOC = (2x -10)° and Angle- BOC = (3x +20)°. find the value of x. Also, find Angle- AOC and BOC.
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We know that (angle AOC ) + (angle BOC) = 180 ° ( linear pair)
Therefore ,
(2x-10) + (3x+20) = 180
5x +10 = 180
x= 170/5
x=34°
Angle AOC = 58°
Angle BOC= 122°
Therefore ,
(2x-10) + (3x+20) = 180
5x +10 = 180
x= 170/5
x=34°
Angle AOC = 58°
Angle BOC= 122°
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