Question

7. In the given figure PQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR . Prove that
ROS=½(QOS-POS)​

Answer 1

See in attachment OR. follow the answer below

$\huge\mathbb{\red{BTS♡EXO }}$

It is given that OR is perpendicular to PQ

So that ∠POR = 90°

sum of angle in linear pair always equal to 180°

∠POS + ∠SOR + ∠POR = 180°

Plug ∠POR = 90°

90°+∠SOR + ∠POR = 180°

∠SOR + ∠POR = 90°

∠ROS = 90° − ∠POS ..… (1)

∠QOR = 90°

Given that OS is another ray lying between rays

OP and OR so that

∠QOS − ∠ROS = 90°

∠ROS = ∠QOS − 90° .....(2)

On adding equations (1) and (2), we obtain

2 ∠ROS = ∠QOS − ∠POS

∠ROS = 1/2(∠QOS − ∠POS)

${\huge{\fcolorbox{black}{WHITE}{♡Itz \: innocent\:girl \: AISH♡}}}$

Answer 2

Step-by-step explanation:

Just Mark me as brainlist