Question

7. One requires 0.01 mole of NaOH. The mass of NaOH to be taken is (A) 0.04 g B) 0.4 (C) 4.0 (D) 0.4g .please help me to find out answer of this question with proper explanation. ​

Answer 1

Answer:

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The Molarity of a solution is determined by the comparison of the moles of the solute compared to the volume of the solution in liters.molThe equation of the formula is M = L In order to find the mass we first need to solvefor the moles.mol M L -M = 0.400 moles = ?L = 250.0mL or 0.25 L0.400M (0.25L) = (?mol)0.100molof NaOHNow we can calculate the grams be converting moles to grams.Na = 22.98gO = 15.99 g0 = 15.99g H = 1.01 gH = 1.01gNaOH = 39.98 gNaOH = 39.98g0.100 cancel(mol NaOH) x (39.98 g NaOH)/(1 cancel(molNaOH)0.100 molNaOH x 39.98gNaOH 1molNaOH

Answer 2

Explanation:

Answer:

$\sf\fbox\red{Answer:-}$

Answer:-

The Molarity of a solution is determined by the comparison of the moles of the solute compared to the volume of the solution in liters.molThe equation of the formula is M = L In order to find the mass we first need to solvefor the moles.mol M L -M = 0.400 moles = ?L = 250.0mL or 0.25 L0.400M (0.25L) = (?mol)0.100molof NaOHNow we can calculate the grams be converting moles to grams.Na = 22.98gO = 15.99 g0 = 15.99g H = 1.01 gH = 1.01gNaOH = 39.98 gNaOH = 39.98g0.100 cancel(mol NaOH) x (39.98 g NaOH)/(1 cancel(molNaOH)0.100 molNaOH x 39.98gNaOH 1molNaOH