Math, asked by iamajkumar1998, 3 months ago

7
Question Number 15
Support ID: DBD2F7
A shopkeeper purchased 10 kilograms of apple costing rupees 100 per kilogram. He also purchased
10 more kilograms of apple costing rupees 80 per kilogram. The employee at his shop mixed both
varieties of apples by mistake. If the shopkeeper needs to make a 25% profit from all the apples, at
what price should he sell each kilogram of mixed apples?
The price per kg in Rupees which he sold the mbcture for is:
Rs.
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Answers

Answered by dualadmire
5

Given:

Cost of 10 kilograms of apples of type 1 = Rs. 100 per kg

Cost of 10 kilograms of apples of type 2 = Rs. 180 per kg

To find:

The price at which the shopkeeper must sell the mixed apples to make a profit of 90%.

Solution:

Cost of 10 kilograms of apples of type 1 = Rs. 100*10 = Rs. 1000

Cost of 10 kilograms of apples of type 2 = Rs. 80*10= Rs. 800

Total cost price of apples = Rs. 1000+800 = Rs. 1800

Profit percent to be made= 25%

Profit= (25/100)*1800

= Rs. 450

Selling price of all the 20 kg apple= Profit+ cost price

= Rs. 450+ Rs. 1800 = Rs. 2250

Selling price of 1 kg of apple = Rs. 2250/20 = Rs. Rs. 112.5

The shopkeeper must sell the apples at a cost of Rs. 112.5 per kg.

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