Math, asked by chaudharisuhani154, 9 months ago

(7) Rationalize the denominator in the following
(1). 1/√7-√6
(2). 1/√5+√2​

Answers

Answered by MoodyCloud
3

 ❶ \frac{1}{ \sqrt{7}  -  \sqrt{6} }

⇢ \frac{1}{ \sqrt{7}  -  \sqrt{6} } \times   \frac{ \sqrt{7}  +  \sqrt{6}  }{ \sqrt{7 +  \sqrt{6} } }

⇢ \frac{ \sqrt{7} +  \sqrt{6}  }{ {( \sqrt{7}) }^{2} -{( \sqrt{6} })^{2}  }

⇢ \sqrt{7}  +  \sqrt{6}

Hence, Rationalised

➋ \frac{1}{ \sqrt{5} +  \sqrt{2}  }

⇢ \frac{1}{ \sqrt{5} -  \sqrt{2}  }  \times  \frac{ \sqrt{5}   +  \sqrt{2} }{ \sqrt{5} +  \sqrt{2}  }

⇢ \frac{ \sqrt{5} +  \sqrt{2}  }{ {( \sqrt{5} )}^{2} -  {( \sqrt{2} })^{2}  }

⇢ \frac{ \sqrt{5} +  \sqrt{2}  }{3}

Hence ,Rationalised

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