Factorise 4(x-3y)³
+12(x-3y)²
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Answer:
4(2x−3y)
2
−8x+12y−3
=4(2x−3y)
2
−4(2x−3y)−3
Let (2x−3y) be a
=4a
2
−4a−3
=4a
2
−6a+2a−3
=2a(2a−3)+1(2a−3)
=(2a−3)(2a+1)
Putting the value of a
=[2(2x−3y)−3][2(2x−3y)+1]
=(4x−6y−3)(4x−6y+1)
hope it helps
Step-by-step explanation:
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