Math, asked by spnajyoti, 3 months ago

7. Shanti Sweets Stall was placing an order for making cardboard boxes for packing
their sweets. Two sizes of boxes were required. The bigger of dimensions
25 cm x 20 cm x 5 cm and the smaller of dimensions 15 cm x 12 cm x 5 cm. For all the
overlaps. 5% of the total surface area is required extra. If the cost of the cardboard is
4 for 1000 cm?, find the cost of cardboard required for supplying 250 boxes of each
kind.

Answers

Answered by rakheepakhee
2

Answer:

Rs. 2184

Step-by-step explanation:

Total S.A of bigger box  

=2(lb+bh+lh)

=2(25×20+25×5+20×5) cm  

2

 

=2(500+125+100)

=1450 cm  

2

 

⇒For overlapping extra area required =  

100

450×5

​  

=72.5 cm  

2

 

∴ Total S.A (including overlaps)

=1450+72.5=1522.5 cm  

2

 

Area of cardboard sheet for 250 such boxes

=(1522.5×250) cm  

2

 

Total S.A of smaller box  

=2(15×12+15×5+12×5)cm  

2

 

=630 cm  

2

 

For overlapping area required =  

100

630×5

​  

=31.5 cm  

2

 

Total S.A (including overlaps)=630+31.5=661.5 cm  

2

 

Area of cardboard sheet required for 250 such boxes

=250×661.5cm  

2

=165375 cm  

2

 

Total cardboard sheet required =380625+165375

=54000 cm  

2

 

⇒Cost of 1000 cm  

2

 cardboard sheet = Rs.4

⇒Cost of 546000 cm  

2

 cardboard sheet  

= Rs.  

1000

546000×4

​  

 

= Rs. 2184

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