Question

7. Show that 6^n cannot end with the digit 0 or 5 for any natural number n.


Standard:- 10


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Answer 1

Note:

Every natural number which ends with digit 0 is divisible by 5.

Therefore, if 6^n ends with the digit 0, it must be divisible by 5.

6^n = (2 * 3)^n


Here, It does not have 5 as a prime factor.

Therefore, 6^n cannot end with the digit 0.



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