Question

7 sin square A + 3 cos square A = 4 then find the value of tangent a​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

7sin²A+3cos²A = 4

=> 4sin²A + (3sin²A+3cos²A)=4

=> 4sin²A + 3(sin²A+cos²A)=4

=> 4sin²A + 3 = 4

=> 4sin²A = 1

=> sin²A = 1/4

=> sin²A = √1/4

=> sinA = 1/2

=> sinA = sin30°

=> A = 30°

Therefore ,

tanA = tan 30° = 1/√3

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