7 sin squared theta + 3 cos square theta is equal to 4 then
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7 sin²θ + 3 cos²θ = 4
∴ 4 sin²θ + 3 sin²θ + 3 cos²θ = 4
∴ 4 sin²θ + 3(sin²θ + cos²θ) = 4
Now, As we know that sin²θ + cos²θ = 1
∴ 4 sin²θ + 3 = 4
∴ 4 sin²θ = 1
∴ sin²θ = 1/4
∴ sinθ = 1/2
∴ sinθ = sin30⁰
∴ θ = 30⁰
Answer:- θ = 30⁰ ; sin30⁰= 1/2 ; cos30⁰ = (√3)/2
∴ 4 sin²θ + 3 sin²θ + 3 cos²θ = 4
∴ 4 sin²θ + 3(sin²θ + cos²θ) = 4
Now, As we know that sin²θ + cos²θ = 1
∴ 4 sin²θ + 3 = 4
∴ 4 sin²θ = 1
∴ sin²θ = 1/4
∴ sinθ = 1/2
∴ sinθ = sin30⁰
∴ θ = 30⁰
Answer:- θ = 30⁰ ; sin30⁰= 1/2 ; cos30⁰ = (√3)/2
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