7 sin2 thetha + 3cos3 thetha =4 then proove that sec thetha + cosec thetha =2/√3 +2
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I will write theta as A
7sin²A+3cos²A=4
4sin²A+3(sin²A+cos²A)=4
4sin²A+3=4
Sin²A=1/4
SinA=1/2
Sin30=1/2
A=30
tan30=1/√3
Hence, tanA=1/√3
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