Question

7 sin²o + 3 cos²o=4, show that
1tan 0 =1/√3​

Answer 1

Answer:

Step-by-step explanation:

$7sin^{2}O +3cos^{2}O =4\\4sin^{2}O+3sin^{2}O +3cos^{2}O =4\\\\4sin^{2}O+3(sin^{2}O+cos^{2}O)=4\\4sin^{2}O+3=4\\4sin^{2}O=1\\sinO=\frac{1}{2} } \\O=30^0\\TAN30^0=\frac{1}{\sqrt{3} }$