Question

if cosec thetha =2/under root 3 , find the value of other five trigonometric ratios​

Answer 1

Step-by-step explanation:

cosec theta= 2/√3 = H/P

let H= 2k, P= √3k

Apply Pythagoras Theorem

(2k)²=(√3k)²+B²

4k²=3k²+B²

B²=1k²

B=√1k²

B=1k

Now, H=2k, P=√3k, B=1k

sin theta= P/H=√3k/2k=√3/2

cos theta=B/H=1k/2k=1/2

tan theta=P/B=√3k/1k=√3

cot theta=B/P=1k/√3k=1/√3

sec theta=H/B=2k/1k=2

Hope you will get it