Question

7.Solve:5(3-x)-2(4-3x)=11-2(x-1)

Answer 1

Given that:- $5(3-x)-2(4-3x)=11-2(x-1)$

As we have to simplify the given expression,

Now, by distributing the terms

$=>5\times 3+5\times(-x)-(2\times(4-3x))=11-2\times (x-1)$

$=>15+5\times (-x)-(2\times(4-3x))=11-2\times(x-1)$

By grouping the like terms,

$=>15-5x-(2\times4-3x)=11-2\times(x-1)$

Expand the parenthesis,

$=>15-5x-8+6x=11-2\times(x-1)$

$=>(-5x+6x)+(15-8)=11-2\times(x-1)$

By simplifying it,

$=>1x+(15-8)=11-2\times(x-1)\\=>1x+7=11-2\times(x-1)\\=>x+7=11-(2x+2\times(-1))\\=>x+7=11-(2x-2)\\=>x+7=-2x+13$

By adding 2x on both side:

$=>x+7+2x=-2x+13+2x$

By grouping like terms,

$=>x+2x+7=-2x+13+2x\\=>3x+7=-2x+13+2x\\=>3x+7=-2x+2x+13\\=>3x+7=13$

Subtract both side by 7 we get,

$=>3x+7-7=13-7\\=>3x=13-7\\=>3x=6$

Divide both sides by 3,

$=>\frac{3x}{3} =\frac{6}{3}$

$=>x=\frac{6}{3}$

The GCF (great common factor) of numerator and the denominator is:-

$=>x=\frac{2\times 3}{1 \times 3}\\=>x=\frac{6}{3}\\=>x=2$

Answer 2

• As per the data given in the question, we have to solve the expression and determine the value of x.

        Given data- $5(3-x)-2(4-3x)=11-2(x-1).$

        To find:- the value of $x$.

        Solution:-

• Firstly, observe the linear equation, and identify the constant and variable terms.
• Simplify the terms and remove the brackets.
• Shift all terms containing variables on LHS constant term on RHS.
• After that, we will simplify and divide both terms with a coefficient of variables.

       Therefore,

       $\Rightarrow 5(3-x)-2(4-3x)=11-2(x-1)\\\Rightarrow 15-5x-8+6x=11-2x+2\\\Rightarrow -5x+2x+6x=11+2+8-15\\\Rightarrow 3x=6\\\Rightarrow x=2.$

      Hence, the value will be $2$.