7. Solve the equation 2(x-2) + 3 (4x-1)=0
Answers
Answer:
here is your answer.......
Answer:
2(x-2) + 3(4x-1) = 0
/* Open the paranthesis , we get */
\implies 2x - 4 + 12x - 3 = 0⟹2x−4+12x−3=0
/* Rearranging the like terms */
\implies 2x + 12x - 4 - 3 = 0⟹2x+12x−4−3=0
\implies 14x - 7 = 0⟹14x−7=0
/* Add both sides by 7 , we get */
\implies 14x - 7 + 7 = 7⟹14x−7+7=7
\implies 14x = 7⟹14x=7
/* On Dividing bothsides by 14, we get */
\implies x = \frac{1}{2}⟹x=
2
1
Therefore.,
\red { Value \: of \: x } \green { = \frac{1}{2}}Valueofx=
2
1
Verification:
Substitute \: x = \frac{1}{2} \: in \:the\: equationSubstitutex=
2
1
intheequation
\begin{gathered}LHS = 2[ \frac{1}{2} - 2 ] + 3[ 4 \times \frac{1}{2}-1] \\= 2[ \frac{1-4}{2}] + 3( 2-1) \\= 2 \times \frac{-3}{2} + 3 \\= - 3 + 3 \\= 0 \\= RHS\end{gathered}
LHS=2[
2
1
−2]+3[4×
2
1
−1]
=2[
2
1−4
]+3(2−1)
=2×
2
−3
+3
=−3+3
=0
=RHS
Step-by-step explanation:
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