7 th term is 40 and 13 th term is 80 what is its 10 th term
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a7 = 40
a7 = a + 6d
40 = a + 6d ...... (1)
a13 = 80
a13 = a + 12d
80 = a + 12d ......(2)
subtract eq (1) , (2)
a + 6d = 40
a + 12d = 80
- - -
- 6d = -40
6d = 40
d = 40/6
d = 20/3
- now a + 6d = 40
a + 6(20/3) = 40
a + 40 = 40
a = 40-40
a = 0
- therefore
a10 = a + 9d
a10 = 0 + 9(20/3)
a10 = 60
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