Question

7. The area of square ABCD is 16 cm. Find the area of the square joining the mid-points of the sides​

Answer 1

Answer:

8 square cm

Step-by-step explanation:

joining the midpoints we get each of the side by Pythagoras theorem as 2 root 2 so the perimeter of the square is square of the length of the square which is (2✓2)^2 square units which is equal to 8 square cm

Answer 2

Answer:

Let the side of big square be b and side of small square be s.

Area of big square = 16cm

2

→b

2

=16cm

2

→b=4cm

Diagonal of the square inside the big square = Side of big square

2

s=b

→

2

s=4

s=2

2

So, Area of small square = s

2

=8cm

2

Thus, The correct answer is A.