Question

7.
The diagonals of a rhombus are 18 cm and
24 om. Find : length of its side​

Answer 1

Answer:

We know that the diagonal of a rhombus bisect each other at right angle.

Draw figure ABCDO

AO =1/2 × AC

AO = 1/2 × 18 = 9

BO = 1/2 × BD

BO = 1/2 × 24 = 12

From right angle AOB

Apply pythagoras theorem

AB Square =AO sq + BO sq

AB sq = 9 sq + 12 sq

AB sq = 81 + 144 = 225

AB = /225 = 15 ANSWER

Answer 2

Answer:

Answer is 15

1. First find 1/2 of each diagonal i.e 24/2 =12 and 18/2=9
2. You found the half of diagonal
3. Now notice that the 1/4 of rhombus is right angled triangle
4. Use pythagoras theorem

Therefore, 9 square +12 square= hyp square

Thus, 81+144= hyp square

$225 = hyp {}^{2}$

$\sqrt{225} = hyp$

Hyp=15