Question

7: The displacement of a particle is represented
by the equation s = 3t^3+ 7t^2 + 5t+8, where s is in metre and t is in second. The acceleration
of the particle at t=is is,
(a) 18 m/s? (b) 32 m/s
(c) zero
(d) 14 m/s​

Answer 1

Answer:

Time u didn't mention man!!!

Explanation:

If time is zero acceleration is 14

If time is one acceleration is 32

If time is something n put in formula a =18t+14

Answer 2

Answer:

a=14m/s²(t=0)

a=32m/s²(t=1)

Explanation:

Given:-

s=3t³+7t²+5t+8

a=?

v= ds

dt

v= d(3t³+7t²+5t+8)

dt

v=9t²+14t+5

a= dv

dt

a= d(9t²+14t+5)

dt

a=18t+14

At t=0sec

a=18(0)+14

a=14m/s²

At t=1sec

a=18(1)+14

a=32m/s²

Hope this helps you

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Thanks for your question.