7) The electric field E due to any point charge near it is defined as E=limq→0 Fq where q is the test charge and F is the force acting on it. What is the physical significance of limq→0 in this expression ? Draw the electric lines of point charge Q when (i) Q > 0 and (ii) Q < 0.
Answers
Answered by
5
In the given question, the law of Coulomb is applied.
Explanation:
- Since charge or charge distribution is described in the question, the charge represented by q which is positioned somewhere in the region. It experiences electrostatic forces.
- In an electric field, this force is described as force per unit charge.
- This force should not alter the true field. It is only possible if the force per unit charge is very high in magnitude.
- Hence the limq is very low, hence it does not distribute force charge.
- While the point charge can be drawn with electric lines towards and outwards the electric field in both cases.
Similar questions