a liquid occupies half of a vessel at a particular temperature. the volume of the unoccupied part remains constant at all temperatures. if 'a' & 'b' are the coefficients of linear and real expansions of a vessel and liquid, then 'b' is?
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Let us suppose the volume of vessel be V,so volume occupied by liquid is V2.Now, If we increase the temperature by ∆T and a is the linear expansion of vessel,then 3a is the volumic expansion of vessel.Now, new volume of vessel=V1+3a∆Tand new volume of liquid=V21+b∆TAccording to question,V1+3a∆T-V21+b∆T=kwhere k=constantV1+3a∆T-V21+b∆T=V2V+3aV∆T-V2-V2×b∆T=V2V1+3a∆T-12-12b∆T=V21+3a∆T-12-12b∆T=121+3a∆T-12b∆T=13a∆T=12b∆Tb=6a.
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