Question

7. The equivalent weight of KMnO4 in acidic medium is
b) 147
c) 73.5
a) 294
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Answer 1

Answer:

Eq wt of KMno4= 158.04/5 = 3

Explanation:

Molecular mass of KMno4 = 158.04g

In acidic medium,

MnO4- + 8H +5e- –> Mn2 + 4H2O (n=5)

KMno4 act as an oxidizer in acidic media

Eq wt = 158.04/5 = 31.61g/equivqlent