Question

7.
The normality of resulting solution obtained by
dilution of 0.2 M. 200 ml, Ca(OH), solution to
1 litre is​

Answer 1

Answer:

Explanation:

No. Of moles=0.2*0.2=0.04 moles

Now molar its=0.04/1=0.04 molar

Normality=n.factor*molarity=2*0.04=0.08 normal

Answer 2

CORRECT QUESTION

What is the normality of resulting solution obtained by dilution of 0.2 M,200 ml, Ca(OH)2 solution to 1 litre?

Answer

The resulting solution is 0.08N

GIVEN

Normality of 200ml Calcium Hydroxide solution = 0.2M

TO FIND

Normality of 1-liter Calcium Hydroxide solution.

SOLUTION

We can simply solve the above problem as follows-

Initial volume of Calcium Hydroxide solution, V1 = 200 ml

Final Volume of Calcium Hydroxide solution, V2 = 1-litre or 1000 ml

We know that,

Normality = Molarity × Van't hoff factor.

Van't hoff factor of Calcium Hydroxide = 2

Normality of 200 ml of Calcium Hydroxide solution, N1 = 2 × 0.2 = 0.4N

Let the Normality of the final solution br N2

According To the Equation Of Normality

N1V1 = N2V2

Putting the values in the above equation we get.

$0.4 \times 200 = N2 \times 1000$

Solving for N2

$N2 = \frac{0.4 \times 200}{1000}$

N2 = 0.08 N.

Hence, The resulting solution is 0.08N

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