Question

7. The population of a town increases by 9% every year. If the present population is 4360, find the
population a year ago.

Answer 1

Step-by-step explanation:

Given, Present population = 4360

Population increases by 9 percent every year. Let the population of the town a year ago be x

So, population in present year should be x * [(1 + (9/100)].

Now, see, this value is equal to 4360

So, x * (109/100) = 4360

So, x = (4360 * 100)/109

This is equal to 4000

So, the population of the town a year ago was 4000.

Answer 2

Answer:

HERE IS YOUR ANSWER

present population (A) =11881

Let population two year back be P

Rate (R) = 9%

Time (T) = 2years

A=P (1+R/100)^t

11881=P(1+9/100)^2

P=11881×(1+100/109)^2

P=11881×(100/109)^2

P=10000

population two years back was Rs. 10,000

HOPE ITS HELP YOU