7. The side BC of an equilateral 3ABC is parallel to x-axis. Find the slope of AB and
the slope of BC
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side BC is parallel to x - axis. means, angle made by BC with x - axis is zero.
hence, slope of BC = tan0° = 0
we know, angle between two sides of an equilateral triangle equals 60°.
so, angle between side BC and side AB = 60°
let slope of AB = m and slope of BC = 0
now, we know
here m1 is the slope of first line and m2 is the slope of 2nd line . theta is angle between two lines (or their slopes ).
put m1 = m and m2 = 0 and theta= 60°
then,
=> tan60° = m
=> m = tan60° = √3
hence, slope of AB = √3
slope of BC = 0
hence, slope of BC = tan0° = 0
we know, angle between two sides of an equilateral triangle equals 60°.
so, angle between side BC and side AB = 60°
let slope of AB = m and slope of BC = 0
now, we know
here m1 is the slope of first line and m2 is the slope of 2nd line . theta is angle between two lines (or their slopes ).
put m1 = m and m2 = 0 and theta= 60°
then,
=> tan60° = m
=> m = tan60° = √3
hence, slope of AB = √3
slope of BC = 0
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4
Solution :
It is given that ,
∆ABC is an equilateral triangle.
BC is parallel to X - axis .
Inclination of AB = x° = 60°
Slope of AB = m
m = tan x°
=> m = tan 60°
m = √3
••••
It is given that ,
∆ABC is an equilateral triangle.
BC is parallel to X - axis .
Inclination of AB = x° = 60°
Slope of AB = m
m = tan x°
=> m = tan 60°
m = √3
••••
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