Question

7. The speedometer readings of a car are shown below.Find the acceleration
TIME
9.25am
9.45am
SPEEDOMETER
36km/h
72km/h​

Answer 1

Answer:

It is given that u=36km/h

V= 72km/h

We have to convert it into m/s ao we will multiply it with 5/18

U=36×5/18=10

V=72×5/18=20

So acceleration =v-u/t

= 20-10/t

The time will be 9:45-9:25=20min

So we will convert it into second

= 20×60

a=20-10/20×60

=10/20×60

1/120

From  newtons 2nd law

V^2-u^2=2as

S=v^2-u^2/2a

=400-100×120/2

=18000m/s