7. The sum of five consecutive positive integers is always divisible by:
(b) 3
(a) 2
(C) 5
(d) 10
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Answer:
The product (n) of any 5 consecutive numbers will always be divisible by 120 and its factors.
n(n+1)(n+2)(n+3)(n+4)
5×4×3×2=120
Answer C:
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