Question

7. The value of k for which the equation
3x2 + 2x (k2 + 1) + k 2 – 3k + 2 = 0 has roots of opposite signs, lies in the interval :
(a) (- infinity , 0)
(b) (-infinity,-1)
(C) (1, 2)
(d) (3/2, 2)​

Answer 1

$\huge{\boxed{\overline{\underline{\mathfrak{\fcolorbox{cyan}{blue}{Answer}}}}}}$

=> k = (1 , 2)

Given:

• Roots are of opposite sign.

• product of roots is negative

=> (k² - 3k + 2)/3 < 0

=> k² - 3k + 2 < 0

=> (k - 1) (k - 2) < 0

=> k = (1 , 2)

silentlover45.❤️

Answer 2

Answer:

$\implies$ options no (C) (1, 2)