Question

7 thieves steal some Diamonds. 2 of the thieves swindle with others and divide the diamonds between each other in 2 equal parts but one Diamond remains left. Then they call one more thief in their swindle and again divide the diamonds in three equal parts but still 1 Diamond remains left.They call every thief one by one and divide those Diamonds but in every situation 1 Diamond remains left but when they call the 7th and the last thief and divide the Diamonds in 7 equal parts then all diamonds allocated equally. Not a single Diamond remains left. Then find the number of Diamonds. Give a proper solution.

Answer 1

Answer:

it is 7 diamonds because when any number is multiplied and we get even it left 1 when it is odd no diamonds left

Answer 2

Answer:

Only be diamond will be left.