Question

7. Three consecutive integers are such that when they are taken in increasing order and
multiplied by 2,3 and 4 respectively, they add up to 74. Find these numbers.​

Answer 1

Answer:

First integer is 7

second integer is 8

third integer is 9

Step-by-step explanation:

let the first integer be x

Second integer be x+1

Third integer be (x+1)+1

=x+2

Multiply the first integer by 2 = 2x

Multiply the second integer by 3= 3(x+1)

Multiply the third integer by 4= 4(x+2)

Given the sum of these integers are 74

2x+3(x+1)+4(x+2)= 74

2x+3x+3+4x+8

9x+ 11 =74

9x =74-11

9x = 63/9

x = 7