7 times a number decreased by the sum of 2 and 4 equal 22 what is the number
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Answer:
Required number (x) = 4
Explanation:
Let the number = x
According to the problem given,
7 times a number decreased by the sum of 2 and 4 equal 22
=> 7x - (2+4) = 22
=> 7x - 6 = 22
=> 7x = 22+6
=> 7x = 28
=> x = 28/7
=> x = 4
Therefore,
Required number (x) = 4
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