7 times of a two digit number equals 4 times the number with digit reversed. Find the number if the sum of its digit is 3?
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Answer:
let X+y=3-------eq(1)
Step-by-step explanation:
7(10x+y)=4(10y+X)
70x+7y=40y+4x
70x-4x=40y-7y
66x=33y
2x=y--------eq(2)
substitute eq(2)ineq(1)
X+y=3
X+2x=3
3x=3
X=1
y=2
therefore original number is 12
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