Question

7. Two bodies of masses m, and m2 are dropped from height hand he, respectively. The ratio of the times taken by them to reach the ground is [al:h- (b)m h:: mhz (c) Vrh (d) m, vh, :myh​

Answer 1

Explanation:

From second equation of motion,

s=ut+

2

1

at

2

Given, u=0, a=g, s

1

=h

1

, s

2

=h

2

h

1

=(1/2)g(t

1

)

2

h

2

=(1/2)g(t

2

)

2

So, h

1

/h

2

=(t

1

)

2

/(t

2

)

2

or(t

1

)/(t

2

)=

h

2

h

1