7. Two numbers are 8.1/3% and 12.1/2% less than the
third numbers respectively. Then find 1st numbers is
what % more than
2nd number.
दो संख्याएं 8.103 प्रतिशत और 12.17 2 प्रशित क्रमानुसार तीसरी संख्या से कम है तो प्रथम संख्या दूसरी संख्या से कितने प्रतिशत ज्यादा है।
(a) 16.2/3%
(b) 14.2/7%
(c) 4.1/6%
(d) 4.16/21%
Answers
Answer:
4.16/21 %
Step-by-step explanation:
Let the third number be x
∴ ∴ ÷→
First number is 8.1/3% = 25/3% less than the third number (25x/300)
∴ First number = x - 25x/300 = (300x -25x)300
=275x/300 = 11x/12
Second number is 12.1/2% less than the third number (25x/200)
∴ Second number = x - 25x/200 = (200x - 25x)/200
= 175x/200 = 7x/8
Difference between first and second number is 11x/12 - 7x/8
= (22x-21x)/24 = x/24
∴ Percentage first number is more than second number
= [(x/24)/(7x/8)] × 100
= 100/21 %
= 4.16/21%
Step-by-step explanation:
let third number is X
other two numbers 8 1/3% and 12 1/2% less
then 1st number is = (100-8 1/3)% of X
=(100-25/3)/100 ×X
=(300-25)/300 ×X
= 275/300 × X
= 11/12 X
and 2nd is = (100-12 1/2)/100 × X
=( 100-25/2)/100 X
= (200-25)/200 X
= 175/200 X
= 7/8 X
different of 1st number and second number=
( 11/12x -7/8X) = ( 22X -21X)/24 =X/24
so 1st number is X/24 more than 2nd number
so x/24/7X/8 ×100% more than
= 1/24 × 8/7 ×100%
= 100/21 %