Math, asked by abhishekrai041, 5 months ago

7. Two numbers are 8.1/3% and 12.1/2% less than the
third numbers respectively. Then find 1st numbers is
what % more than
2nd number.
दो संख्याएं 8.103 प्रतिशत और 12.17 2 प्रशित क्रमानुसार तीसरी संख्या से कम है तो प्रथम संख्या दूसरी संख्या से कितने प्रतिशत ज्यादा है।
(a) 16.2/3%
(b) 14.2/7%
(c) 4.1/6%
(d) 4.16/21%​

Answers

Answered by nmchopra
2

Answer:

4.16/21 %

Step-by-step explanation:

Let the  third number be x

∴ ∴ ÷→

First number is 8.1/3% = 25/3% less than the third number (25x/300)

∴ First number = x - 25x/300 = (300x -25x)300

=275x/300 = 11x/12

Second number is 12.1/2% less than the third number (25x/200)

∴ Second number = x - 25x/200 = (200x - 25x)/200

= 175x/200 = 7x/8

Difference between first and second number is 11x/12 - 7x/8

= (22x-21x)/24 = x/24

∴ Percentage first number is more than second number

= [(x/24)/(7x/8)] × 100

= 100/21 %

= 4.16/21%

Answered by manojpetal
0

Step-by-step explanation:

let third number is X

other two numbers 8 1/3% and 12 1/2% less

then 1st number is = (100-8 1/3)% of X

=(100-25/3)/100 ×X

=(300-25)/300 ×X

= 275/300 × X

= 11/12 X

and 2nd is = (100-12 1/2)/100 × X

=( 100-25/2)/100 X

= (200-25)/200 X

= 175/200 X

= 7/8 X

different of 1st number and second number=

( 11/12x -7/8X) = ( 22X -21X)/24 =X/24

so 1st number is X/24 more than 2nd number

so x/24/7X/8 ×100% more than

= 1/24 × 8/7 ×100%

= 100/21 %

= 4 16/21% more then 2nd number

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