Question

7. Two persons pull a rope towards themselves. Each
person exerts a force of 100 N on the rope. Find the
Young modulus of the material of the rope if it extends
in length by 1 cm. Original length of the rope = 2 m and
the area of cross section = 2 cm2​

Answer 1

Answer:

Y=FlAΔlF=2×100=200 Nl=1 mΔl=0.01 mA=2×10−4 m2So Y=200×12×10−4×0.01Y=108 Nm−

Explanation:

Y=FlAΔlF=2×100=200 Nl=1 mΔl=0.01 mA=2×10−4 m2So Y=200×12×10−4×0.01Y=108 Nm−