7. two sonometre wires of the same material have equal tension. if the ratio of lengths is 2:1 and the ratio of their cross sectional radius is 1:4, then the ratio of their fundamental frequencies is (2:1 / 1:2 / 1:1 / √2:1)
Answers
Answered by
0
Answer:
Given ;
n 1/n 2 = 1/ 2
T 1/T 2 = 1/ 8
n =( 1/2l)√( T/2m)
n1=(1/2l1) √ (T1/m)
l1=1/2n1 √ (T1/m) ----1
for second case
n2=(/2) l2√(T2/m)
l2=(1/2)n2 √( T2/m) -----1
[m is constant because both wires are made of same material]
Divide (i) by (ii)
l1/l2=n2/n2 √ (T1/T2)
=(2/1) √(1/8)
l1/l2=0.707 : 1
Answered by
3
Explanation:
Given :
r
2
r
1
=
3
2
T
2
T
1
=
4
1
v=
m/l
T
=
ρπr
2
T
so,
v
2
v
1
=
ρπr
2
2
T
2
ρπr
1
2
T
1
Given :
r
2
r
1
=
3
2
T
2
T
1
=
4
1
v=
m/l
T
=
ρπr
2
T
so,
v
2
v
1
=
ρπr
2
2
T
2
ρπr
1
2
T
1
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