7. Two taps A and B fill a tank in 10 hours and 12 hours respectively. An outlet
C can empty the completely filled tank in 15 hours. How long will it take to
fill the empty tank if all the three taps are opened simultsneously?
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Answer:
Step-by-step explanation:
tap-A can fill the tank in = 12- hours. Tap-B can empty the tank in = (10 x2)= 20- hours. So the tank can be completely filled in = 12 x 20/(20–12)= 240/8 = 30- hours.
The time required to half the tank =30/2= 15- hours =××=×==×=×=×=×=×=×=×=×=×=×=×=×=×
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