Question

7 upon root 3 + root 2 rationalization​

Answer 1

$\frac{7}{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

$\frac{7 \sqrt{3} - 7 \sqrt{2} }{ {( \sqrt{3}) }^{2} - {( \sqrt{2}) }^{2} }$

$\frac{7 \sqrt{3} - 7 \sqrt{2} }{3 - 2}$

$\frac{7 \sqrt{3} - 7 \sqrt{2} }{1}$

$7 \sqrt{3} - 7 \sqrt{2}$