Math, asked by anu384681, 4 months ago

7 upon root 3 + root 2 rationalization​

Answers

Answered by GPGAMER9128
0

 \frac{7}{ \sqrt{3}  +  \sqrt{2} }  \times   \frac{ \sqrt{3}  -  \sqrt{2} }{ \sqrt{3}  -  \sqrt{2} }

 \frac{7 \sqrt{3}  - 7 \sqrt{2} }{ {( \sqrt{3}) }^{2} -   {( \sqrt{2}) }^{2}   }

 \frac{7 \sqrt{3} - 7 \sqrt{2}  }{3 - 2}

 \frac{7 \sqrt{3} - 7 \sqrt{2}  }{1}

7 \sqrt{3}  - 7 \sqrt{2}

Similar questions