Question

7. What is the maximum height attained by a ball
thrown vertically upward with speed 10 m/s? [Taken downward acceleration = 10 m/s²​

Answer 1

From the 3rd equation of motion,

v^2 = u^2 +2gh

0 = u^2 - 2g(h/2)

h = u^2/g

= 10^2/10 = 10m

This the ball rise to the maxum height of, 10m.

ANSWER = 10m

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