Question

7. When a ray of light is incident on a plane mirror at an angle theta, the reflected ray deviates through an angle a.π/2 b.π c.π-theta d.π-2 theta​

Answer 1

Answer:

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Initially when mirror is at A position, lets incident ray makes an angle θ with normal.

Now, in case of B, mirror turned by,

θ=

2

1

×2π×(

2

1

)

2

=

16

π

rad

So, in this case i makes, (θ+

16

π

)

Angle with N

′

(new normal) also, refracted ray makes (

16

π

+θ) angle with N

′

.

Previously r makes θ angle with N and now N makes

16

π

rad angle with N

′

.

thereforer makes [(θ+

16

π

)+(

16

π

−θ)]㎭

angle with r.

that is,

16

π

+θ−θ+

16

π

=

8

π

=22.5°

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