Question

$7. When a two digit number is added to the number
obtained by interchanging the digits, the sum |
becomes 110. The difference of the two digits is
6. How many such numbers are there and what
are these numbers?​

Answer 1

Answer:

2 numbers are possible i.e,82 and 28

Step-by-step explanation:

Let the digit at tens place be x and at ones place be y.

So number is 10x+y

After interchanging places number becomes 10y+x.

Sum=110Given

10x+y+10y+x=11x+11y

11x+11y=110

x+y=10

x-y=6

Adding both,

2x=16

x=8

and y =2

So two numbers can be possible 82

and 28 if we take 10y+x as number