If α,β are the zeroes of the polynomial x²-9 then αβ(α+β) is
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Step-by-step explanation:
x²-9=(x+3)(x-3)....by identity x²-y²=(x+y)(x-y)
So a=-3 and ß=3
aß=(-3)(3)=-9
a+ß=-3+3=0
(a+ß)aß=(-9)(0)=0
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