Question

7(y+3)-2(x+2)=14 4(y-2)+3(x-3)=2 by elimination method Please help!!!!!

Answer 1

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7(y+3)-2(x+2)=14

7y+21-2x-4=14

7y-2x=14-17

7y-2x= -3.............(i)

4(y-2)+3(x-3)=2

4y-8+3x-9=2

4y+3x=2+17

4y+3x=19..............(ii)

Multiplying (i) by 3 and (ii) by 2

7y-2x= -3

21y-6x= -9..............(iii)

4y+3x=19

8y+6x=38................(iv)

Adding (iii) and (iv),

21y-6x+8y+6x = 38-9

29y = 29

y=1

putting value of y in (i),

7y-2x= -3

7(1)-2x = -3

-2x = -3-7

x = -10/-2

x=5