Question

70 calories of heat is required to raise the temperature of 2 moles of an ideal gas

Answer 1

Answer:

Cp= q/n*delta t

= 70/2*5=7

We know that for diatomic gas

Cp/Cv=7/5

So Cv=5

Cv=q/n*delta t

5=q/2*5

q=50 calories

Hope it helps you

Explanation: