Question

Calculate the number of molecules present in 44.8 cm3 of oxygen gas

Answer 1

Answer:

Pressure=2 atm

Temp.=273 K

Volume=44.8 cm3=44.8 litre

So,

By PV=nRT

n=PV/RT

mole=(2 x 44.8)/(0.0821 x 273)

So, no. of mole=3.998=4

So, no. of molecule=4 x 6.023 x 10^(23)

=24.08 x 10^(23)

Explanation: