Question

70 kg man pushes a 50 kg man by a forse of 50N .By what force 50 kg man pushedthe other man t

Answer 1

in this question Solve by using .
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GIVEN,

70kg person pushes a 50kg man by a force of 50N .


So, Let force = 50N

now, normal reaction act on 50 kg man = mg

mg = 500N

we know, friction is directly proportional to normal reaction then,

fr = kN ,
k is coefficient of static friction and N is normal reaction.

now, for balancing fr = F

so, 50 = kN

50 = k × 500

k = 50/500

K = 0.1 ,

hence coefficient of static Friction = 0.1

Let F' force act by 50kg man on 70 kg man

then, F' = static Friction act on 70kg man

= coefficient of static friction × normal reaction act on 70 kg man

= 0.1 × 70 × 10 [ g = 10 m/s² ]


= 70N​

Answer 2

Given:

Mass of man1 = 70 kg

Mass of man2 = 50 kg

Force = 50 N

To find:

The force needed by man2 to push man1

Solution:

By formula,

Normal= Mass * Gravity

Where,

Gravity = 9.8 m / s

Substituting,

50 × 9.8

Normal = 490 N

To find friction,

Friction = r * Normal  

Where,  

r is coefficient of static friction

We know,

Ideally,

Frictional Force = Normal Reaction Force.  

∴ 50 = r × N  

50 = r × 490

r = 0.102

Hence,

Force = 0.102 × 70 × 9.8

Force = 69.9 N

Therefore, Force ≅ 70 N

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