Question

700kg of mortar consisits of 53% sand, 129 kg of cement and the rest lime. What percent of the lime is there in mortar?

Answer 1

$\huge\mathbb{HOLA}$

$\huge\bold{Answer}$

$\bold{Quantity\:of\:mortar\:=\:700kg}$

$\bold{Quantity\:of\:sand}$ = 53% of mortar

= 53% of 700

=371 kg

$\bold{Weight\:of\:sand\:=\:371kg}$

$\bold{Weight\:of\:lime\:=\:129kg}$

weight of Mortar= weight of sand+ weight of cement +weight of lime

Let the weight of lime be = $\bold{x\:kg}$

700kg = 371kg+129kg+ x kg

700kg = 500kg+ x kg

x = 700-500

x= 200

Therefore,

$\bold{weight\:of\:lime\:=\:200kg}$

$\bold{Percent\:of\:lime\:in\:mortar}$ = 200/700×100= 28.571%

$\huge\mathfrak{Thank-you}$